The Emperor's Holiday
The Emperor's Holiday is a Continuous Trap, first released in 2003 in Labyrinth of Nightmare (Worldwide English). It has 5 printings across 3 sets (Common). The cheapest copy is LON-E087 Common at $0.11; the most valuable is LON-EN087 Common at $0.99. In the TCG it is currently unlimited (3 copies).
Market price · TCGPlayer
Updated Oct 1, 2026
$0.11 – $0.99
5 printings priced
Type
Continuous
ATK
0
DEF
0
Negate the effects of all Equip Spell Cards.
Appears in 3 expansions
Printings (5)
| expansion | Code | Rarity | Price | Buy |
|---|---|---|---|---|
| Labyrinth of Nightmare (Europe) | LON-E087 | Common | $0.11 | |
| Labyrinth of Nightmare | LON-087 | Common | $0.22 | |
| Dark Beginning 2 | DB2-EN020 | Common | $0.13 | |
| Turbo Pack: Booster Eight | TU08-EN017 | Common | $0.11 | |
| Labyrinth of Nightmare (Worldwide English) | LON-EN087 | Common | $0.99 |
The Emperor's Holiday: FAQ
How much is The Emperor's Holiday worth?+
The Emperor's Holiday currently sells for $0.11 – $0.99 on TCGPlayer, from $0.11 for LON-E087 up to $0.99 for LON-EN087. The exact value depends on the printing, rarity, edition and condition — scan the card with YuScan to see the price of your copy.
Which sets was The Emperor's Holiday printed in?+
The Emperor's Holiday appears in 3 sets: Labyrinth of Nightmare (Worldwide English), Dark Beginning 2, Turbo Pack: Booster Eight.
Is The Emperor's Holiday legal in tournaments?+
On the current TCG Forbidden & Limited List, The Emperor's Holiday is unlimited (3 copies).
What is the passcode of The Emperor's Holiday?+
The 8-digit passcode printed on The Emperor's Holiday is 68400115.
What is your collection worth?
YuScan identifies any Yu-Gi-Oh! card with your camera and tracks live prices per printing across five marketplaces — so a 1st Edition never gets averaged with an Unlimited.
